A particle is moving along the x axis so that its distance x in meters,at time t seconds,is x(t)=3,2(sqrt of tan (5t)).Find its velocity at time t=1,5 seconds.

Answer 1

x(t) = 3.2√tan(5t)
= 3.2(tan(5t))^(1/2)
x ' (t) = 3.2(1/2)(tan(5t))^(-1/2) (5sec^2 (5t) )

plug in t = 1.5
- make sure your calculator is set to radians