A particle has an initial horizontal velocity of 1.8 m/s and an initial upward velocity of 4.7 m/s. It is then given a horizontal acceleration of 2.3 m/s2 and a downward acceleration of 1.6 m/s2.

Question

What is its speed after 1.9 s?
Answer in units of m/s.

What is the direction of its velocity at this time with respect to the horizontal?
Answer between −180 degrees and +180 degrees.
Answer in units of degrees.

Answer 1

2.3*t gets added to the initial horizontal velocity component (1.8)

1.6*t gets subtracted from the initial vertical velocity component (+4.7).

Compute the resulting velocity components at t = 1.9s, and then compute the magnitude(speed)using the Pythagorean theorem.

The ratio of the velocity components. Vy/Vx, is the tangent of the angle they are asking for.