d = (1/2)(3)t^2
so
t = sqrt [ (2/3)(200)] = sqrt (400/3)
=20/sqrt3
= 11.5 seconds
v = a t = 3 (11.5) = 34.6 m/s
A particle accelerates from rest at a uniform rate of 3 m/s^2 for a distance of 200m.
-how fast s the particle going at that time?
-how long did it take for the particle to reach that velocity?
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