To solve Part A, we want to find the equation that represents the situation where Kiera and Tiauna have paid the same amount after a certain number of months.
Kiera's cost after \( m \) months is:
- \( 1.25m \)
Tiauna's cost after \( m \) months is:
- She gets her first 2 issues free, so after 1 month, she pays $1.50. After 2 months she pays $1.50 × 2, but the first two issues are free, so starting from the third month, she pays for the remaining months:
- Her cost after \( m \) months will be \( 1.50(m - 2) \) for \( m \geq 2 \).
Thus, the equation to find when they paid the same is: \[ 1.25m = 1.50(m - 2) \]
So the correct answer for Part A is: C: \( 1.25m = 1.50(m - 2) \)
For Part B, we'll solve the equation \( 1.25m = 1.50(m - 2) \):
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Expand the right side: \[ 1.25m = 1.50m - 3.00 \]
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Rearrange the equation: \[ 1.25m - 1.50m = -3.00 \] \[ -0.25m = -3.00 \]
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Divide both sides by -0.25: \[ m = \frac{-3.00}{-0.25} = 12 \]
Therefore, after 12 months, the girls will have paid the same amount.
In summary:
- Part A: C
- Part B: 12 months.