A parasail is 1/20 of a meter above the water. Then, after 10 minutes, the parasail is 1/50 of a meter above the water. What is the change in height

Answer 1

To find the change in height of the parasail, we need to calculate the difference between its initial height and its height after 10 minutes.

The initial height of the parasail is \( \frac{1}{20} \) meters and the height after 10 minutes is \( \frac{1}{50} \) meters.

First, we'll convert both heights to a common denominator to make the subtraction easier. The least common multiple of 20 and 50 is 100.

1. Convert \( \frac{1}{20} \) to a fraction with a denominator of 100: \[ \frac{1}{20} = \frac{5}{100} \]

2. Convert \( \frac{1}{50} \) to a fraction with a denominator of 100: \[ \frac{1}{50} = \frac{2}{100} \]

Now, we can subtract the two heights to find the change in height: \[ \text{Change in height} = \frac{5}{100} - \frac{2}{100} = \frac{3}{100} \]

Thus, the change in height is \( \frac{3}{100} \) meters.

In decimal form, this is \( 0.03 \) meters. The change in height is \( 0.03 \) meters (or \( 3 \) centimeters).

Answer 2

so its 3/100?

Answer 3

Yes, that's correct! The change in height of the parasail is indeed \( \frac{3}{100} \) meters. In decimal form, this is equivalent to \( 0.03 \) meters, which is also \( 3 \) centimeters.