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Original Question
A parasail is 120 of a meter above the water. Then, after 10 minutes, the parasail is 150 of a meter above the water. What is t...
A parasail is 1/20 of a meter above the water. Then, after 10 minutes, the parasail is 1/50 of a meter above the water. What is the change in height?(1 point)
Responses
120 meter
Start Fraction 1 over 20 End Fraction meter
7100 meter
Start Fraction 7 over 100 End Fraction meter
3100 meter
Start Fraction 3 over 100 End Fraction meter
150 meter
Responses
120 meter
Start Fraction 1 over 20 End Fraction meter
7100 meter
Start Fraction 7 over 100 End Fraction meter
3100 meter
Start Fraction 3 over 100 End Fraction meter
150 meter
Answers
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Answered by
GPT-4o mini
To find the change in height of the parasail, we need to calculate the difference between the starting height and the ending height.
1. Initial height = \( \frac{1}{20} \) meter
2. Final height = \( \frac{1}{50} \) meter
We can convert both fractions to a common denominator to make the subtraction easier. The least common multiple of 20 and 50 is 100.
Now, let's convert both fractions:
\[
\frac{1}{20} = \frac{5}{100}
\]
\[
\frac{1}{50} = \frac{2}{100}
\]
Now we can calculate the change in height:
\[
\text{Change in height} = \text{Initial height} - \text{Final height}
\]
\[
\text{Change in height} = \frac{5}{100} - \frac{2}{100} = \frac{3}{100}
\]
Thus, the change in height is \( \frac{3}{100} \) meter.
The correct response is:
\( \frac{3}{100} \) meter.
1. Initial height = \( \frac{1}{20} \) meter
2. Final height = \( \frac{1}{50} \) meter
We can convert both fractions to a common denominator to make the subtraction easier. The least common multiple of 20 and 50 is 100.
Now, let's convert both fractions:
\[
\frac{1}{20} = \frac{5}{100}
\]
\[
\frac{1}{50} = \frac{2}{100}
\]
Now we can calculate the change in height:
\[
\text{Change in height} = \text{Initial height} - \text{Final height}
\]
\[
\text{Change in height} = \frac{5}{100} - \frac{2}{100} = \frac{3}{100}
\]
Thus, the change in height is \( \frac{3}{100} \) meter.
The correct response is:
\( \frac{3}{100} \) meter.
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