Question

A parasail is 1/20 of a meter above the water. Then, after 10 minutes, the parasail is 1/50 of a meter above the water. What is the change in height?(1 point)

Answer 1

To find the change in height of the parasail, we subtract the final height from the initial height.

The initial height is \( \frac{1}{20} \) meters, and the final height is \( \frac{1}{50} \) meters.

First, we need a common denominator to perform the subtraction. The least common multiple of 20 and 50 is 100.

Now we convert both fractions:

\[
\frac{1}{20} = \frac{5}{100}
\]
\[
\frac{1}{50} = \frac{2}{100}
\]

Now we can subtract the final height from the initial height:

\[
\text{Change in height} = \frac{1}{20} - \frac{1}{50} = \frac{5}{100} - \frac{2}{100} = \frac{3}{100}
\]

Therefore, the change in height is \( \frac{3}{100} \) meters, which is equivalent to 0.03 meters.