Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
A parasail is 120 of a meter above the water. Then, after 10 minutes, the parasail is 150 of a meter above the water. What is t...Asked by optional
A parasail is 1/20 of a meter above the water. Then, after 10 minutes, the parasail is 1/50 of a meter above the water. What is the change in height?(1 point)
Responses
1/20 meter
Start Fraction 1 over 20 End Fraction meter
7/100 meter
Start Fraction 7 over 100 End Fraction meter
3/100 meter
Start Fraction 3 over 100 End Fraction meter
1/50 meter
Responses
1/20 meter
Start Fraction 1 over 20 End Fraction meter
7/100 meter
Start Fraction 7 over 100 End Fraction meter
3/100 meter
Start Fraction 3 over 100 End Fraction meter
1/50 meter
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the change in height of the parasail, we need to subtract the final height from the initial height.
1. Initial height: \( \frac{1}{20} \) meters
2. Final height: \( \frac{1}{50} \) meters
We first need a common denominator to perform the subtraction. The least common multiple of 20 and 50 is 100.
Now, let's convert both fractions to have a denominator of 100:
- \( \frac{1}{20} = \frac{1 \times 5}{20 \times 5} = \frac{5}{100} \)
- \( \frac{1}{50} = \frac{1 \times 2}{50 \times 2} = \frac{2}{100} \)
Now, we can subtract the final height from the initial height:
\[
\text{Change in height} = \frac{5}{100} - \frac{2}{100} = \frac{3}{100} \text{ meters}
\]
Therefore, the change in height is \( \frac{3}{100} \) meters.
The correct response is:
**3/100 meter**
(Start Fraction 3 over 100 End Fraction meter)
1. Initial height: \( \frac{1}{20} \) meters
2. Final height: \( \frac{1}{50} \) meters
We first need a common denominator to perform the subtraction. The least common multiple of 20 and 50 is 100.
Now, let's convert both fractions to have a denominator of 100:
- \( \frac{1}{20} = \frac{1 \times 5}{20 \times 5} = \frac{5}{100} \)
- \( \frac{1}{50} = \frac{1 \times 2}{50 \times 2} = \frac{2}{100} \)
Now, we can subtract the final height from the initial height:
\[
\text{Change in height} = \frac{5}{100} - \frac{2}{100} = \frac{3}{100} \text{ meters}
\]
Therefore, the change in height is \( \frac{3}{100} \) meters.
The correct response is:
**3/100 meter**
(Start Fraction 3 over 100 End Fraction meter)
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.