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Original Question
A parasail is 120 of a kilometer above the water. Then, after 10 minutes, the parasail is 150 of a kilometer above the water. W...Asked by Mr.CheatSheet
                A parasail is  1/20  of a kilometer above the water. Then, after 10 minutes, the parasail is  1/50  of a kilometer above the water. What is the difference in height?(1 point)
Responses
7100 kilometers
Start Fraction 7 over 100 End Fraction kilometers
150 kilometers
Start Fraction 1 over 50 End Fraction kilometers
120 kilometers
Start Fraction 1 over 20 End Fraction kilometers
3100 kilometers
Start Fraction 3 over 100 End Fraction kilometers
            
        Responses
7100 kilometers
Start Fraction 7 over 100 End Fraction kilometers
150 kilometers
Start Fraction 1 over 50 End Fraction kilometers
120 kilometers
Start Fraction 1 over 20 End Fraction kilometers
3100 kilometers
Start Fraction 3 over 100 End Fraction kilometers
Answers
                                                    There are no human answers yet.
                                            
                
                    Answered by
            GPT-4o mini
            
    To find the difference in height between the two heights of the parasail, we start with the given heights:
1. First height: \( \frac{1}{20} \) kilometers
2. Second height: \( \frac{1}{50} \) kilometers
To find the difference, we subtract the second height from the first height:
\[
\frac{1}{20} - \frac{1}{50}
\]
To perform this subtraction, we need a common denominator. The least common multiple of 20 and 50 is 100. We convert each fraction:
\[
\frac{1}{20} = \frac{5}{100} \quad \text{(because } 1 \times 5 = 5 \text{ and } 20 \times 5 = 100\text{)}
\]
\[
\frac{1}{50} = \frac{2}{100} \quad \text{(because } 1 \times 2 = 2 \text{ and } 50 \times 2 = 100\text{)}
\]
Now we can subtract:
\[
\frac{5}{100} - \frac{2}{100} = \frac{5 - 2}{100} = \frac{3}{100}
\]
Thus, the difference in height is \( \frac{3}{100} \) kilometers.
Looking at your options, the correct response is:
**Start Fraction 3 over 100 End Fraction kilometers**.
    
1. First height: \( \frac{1}{20} \) kilometers
2. Second height: \( \frac{1}{50} \) kilometers
To find the difference, we subtract the second height from the first height:
\[
\frac{1}{20} - \frac{1}{50}
\]
To perform this subtraction, we need a common denominator. The least common multiple of 20 and 50 is 100. We convert each fraction:
\[
\frac{1}{20} = \frac{5}{100} \quad \text{(because } 1 \times 5 = 5 \text{ and } 20 \times 5 = 100\text{)}
\]
\[
\frac{1}{50} = \frac{2}{100} \quad \text{(because } 1 \times 2 = 2 \text{ and } 50 \times 2 = 100\text{)}
\]
Now we can subtract:
\[
\frac{5}{100} - \frac{2}{100} = \frac{5 - 2}{100} = \frac{3}{100}
\]
Thus, the difference in height is \( \frac{3}{100} \) kilometers.
Looking at your options, the correct response is:
**Start Fraction 3 over 100 End Fraction kilometers**.
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