Let the height of the triangle be h.
The area of the parallelogram is base times height, so it's 8*4 =<<8*4=32>>32 square inches.
Since both shapes have the same area, the area of the triangle is also 32 square inches. The area of a triangle is 1/2 * base * height, so:
32 = 1/2 * 8 * h
To find the height of the triangle, we can multiply both sides of the equation by 2:
64 = 8*h
Finally, we can divide both sides of the equation by 8:
h = 8
So the height of the triangle is 8 inches.
A parallelogram and a triangle both have a base of 8 inches. The height of the parallelogram is 4 inches. What is the height of the triangle if both shapes have the same area
1 answer