Question

A parabola representing a quadratic equation has x-intercepts at (1,0)
and (3,0)
and a third point with coordinates at (4,3)
. Which quadratic equation in intercept form accurately represents this information?(1 point)
Responses

y=−1(x−1)(x−3)
y is equal to negative 1 open paren x minus 1 close paren open paren x minus 3 close paren

y=1(x+1)(x−3)
y is equal to 1 open paren x plus 1 close paren open paren x minus 3 close paren

y=1(x−1)(x−3)
y is equal to 1 open paren x minus 1 close paren open paren x minus 3 close paren

y=1(x−1)(x+3)

Answer 1

To find the quadratic equation in intercept form that has x-intercepts at (1,0) and (3,0) and passes through the point (4,3), we start with the intercept form of the quadratic equation:

\[ y = a(x - p)(x - q) \]

where \( p \) and \( q \) are the x-intercepts of the parabola.

From the given information, we have:
- \( p = 1 \)
- \( q = 3 \)

Thus, the equation becomes:

\[ y = a(x - 1)(x - 3) \]

Next, we need to find the value of \( a \) using the additional point (4,3). Substituting \( x = 4 \) and \( y = 3 \) into the equation gives:

\[ 3 = a(4 - 1)(4 - 3) \]
\[ 3 = a(3)(1) \]
\[ 3 = 3a \]
\[ a = 1 \]

Now we can write the complete quadratic equation:

\[ y = 1(x - 1)(x - 3) \]
or simply,

\[ y = (x - 1)(x - 3) \]

Therefore, the correct answer is:

**y = 1(x−1)(x−3)**

This corresponds to the response:

y is equal to 1 open paren x minus 1 close paren open paren x minus 3 close paren.