To identify the vertex and axis of symmetry of a parabola, we need the standard form of the quadratic equation, which is typically given as \( y = ax^2 + bx + c \).
If you have specific coordinates of points on the parabola or its equation, please share that information. Without seeing the graph or having an equation, I can guide you on how to find the vertex and axis of symmetry in general terms:
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Axis of Symmetry: The axis of symmetry for a parabola given by the equation \( y = ax^2 + bx + c \) can be found using the formula: \[ x = -\frac{b}{2a} \]
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Vertex: The vertex of the parabola can be found using the x-coordinate from the axis of symmetry. Once you find \( x \), substitute it back into the original equation to find the corresponding y-coordinate: \[ y = a(-\frac{b}{2a})^2 + b(-\frac{b}{2a}) + c \]
If you have a specific equation or additional information about the parabola, please provide that, and I can assist you further in finding the exact vertex and axis of symmetry.