A parabola has intercepts of x = -2, x = 3, and y = -4

Question

how do I write this into these forms:

the intercept form (y = a (x – m)(x – n))
and
in standard (y = ax2 + bx + c) form

Answer 1

see
https://www.jiskha.com/display.cgi?id=1523149457
for the first part. I'm sure you can expand it and rearrange terms to get the standard form. If not, show what you come up with.

Answer 2

Well for the intercept form, I wrote -4 = a ( -2 – m) ( 3 – n) but I don't know which x to use for the standard form for a or b. or am i supposed to put the values of x's like this in standard form

(y = ax^2 + bx + c)
y = a -2^2 + b3 + c