A parabola has intercepts of x = -2, x = 3, and y = -4

how do I write this into these forms:

the intercept form (y = a (x – m)(x – n))
and
in standard (y = ax2 + bx + c) form

2 answers

see
https://www.jiskha.com/display.cgi?id=1523149457
for the first part. I'm sure you can expand it and rearrange terms to get the standard form. If not, show what you come up with.
Well for the intercept form, I wrote -4 = a ( -2 – m) ( 3 – n) but I don't know which x to use for the standard form for a or b. or am i supposed to put the values of x's like this in standard form

(y = ax^2 + bx + c)
y = a -2^2 + b3 + c
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