weight of water displaced = 6.95 - 4.26 = 2.69 N
2.69 N = Vol * 1000Kg/m^3 * 9.81 m/s^2
so
Yes
A paperweight, when weighed in air, has a weight of W = 6.95 N. When completely immersed in water, however, it has a weight of Win water = 4.26 N. Find the volume of the paperweight.
Would I multiply the two values of weight and then by the density of water?
4.26=weightinair-forcebouyancy
4.26=6.95-desnisitywater*g*volume
solve for volume
So would I set it up as
4.26= 6.95 - 1000(9.8)V ?
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