A palm fruit drops to the ground from the top of a tree 5m tall. How long does it take to reach the ground.
2 answers
5t^2 = 5
a = -g = -10 m/s^2
v = Vi + a t = 0 -10 t m/s
h = Hi + Vi t + (1/2) a t^2 = 0 + 0 - (10/2) t^2 meters
h = 5 - 5 t^2
when h = 0
t^2 = 5/5 = 1
t = 1 second
v = Vi + a t = 0 -10 t m/s
h = Hi + Vi t + (1/2) a t^2 = 0 + 0 - (10/2) t^2 meters
h = 5 - 5 t^2
when h = 0
t^2 = 5/5 = 1
t = 1 second