A paladin howitzer fires a 46.00 kg projectile towards a 1000 kg metal block resting on a frictionless surface. Just before impact, the projectile is traveling with a horizontal velocity of 529 m/s. After the collision, the embedded projectile and the metal block move along the frictionless surface continuing in the same direction. Calculate the final velocity of the projectile-metal block system. (Assume the projectile embeds in the metal block and does NOT explode, and neglect air resistance.)

Question

A paladin howitzer fires a 46.00 kg projectile towards a 1000 kg metal block resting on a frictionless surface.  Just before impact, the projectile is traveling with a horizontal velocity of 529 m/s.  After the collision, the embedded projectile and the metal block move along the frictionless surface continuing in the same direction.  Calculate the final velocity of the projectile-metal block system.    (Assume the projectile embeds in the metal block and does NOT explode, and neglect air resistance.)

~ I have tried this one like 5 times... i just don't get it, can someone explain it to me~

Henry · Answer

Conservation of momentum: Total momentum before the collision = Total momentum after the collision. M1*V1+M2*V2 = M1*V+M2*V = (M1+M2)*V 46*529 + 1000*0 = 1046*V Solve for V.

Anonymous · Answer

ur so dumb its so easy