Your question makes little sense.
The sum on the two dice is between 2 and 12
What's with all the weird numbers?
ok,
a) the prob of rolling a sum not more than 1010 = 1
b) prob of sum less than 77 = 1
so prob of sum not less than 77 = 0
c) prob of sum between 33 and 77 ??
there are 3 such numbers, namely 34, 35, and 36
so prob(of your event) = 3/36 = 1/12
A pair of dice is rolled. Find the probability of rolling
a) a sum not more than 1010,
b) a sum not less than 77,
c) a sum between 33 and 77 (exclusive).
1 answer
1 answer