A painter working at 100 feet from the ground, drops his paint brush onto the street below. The function,

Question

s(t)=-16t^2+100, gives the height(in feet) of the paint brush as it falls to the ground. The velocity at time t=2 seconds is given by

lim s(2)-s(t)/2-t
t-->2

Evaluate this limit to find the velocity of the paint brush at 2 seconds. (include units in your answer).

Answer 1

again, you typed it wrong
should be

lim ( s(2) - s(t))/(2-t) as t ---> 2
= lim (36 + 16t^2 - 100)/(2-t)
= lim (16(t^2 - 4)/(2-t)
= lim 16(t+2)(t-2)/(2-t)
= lim 16(-1)(t+2) as t --->2
= 16(-1)(4) = -64

Answer 2

Thank You!!

Answer 3

so did this help