y = 2x^3 + kx - 5
y' = 6x^2 + k
so, you want
6+k = -2
k = -8
so,
y = 2x^3-8x-5
since the slope is -2 at x=1,
y(1) = -11
The normal has slope m = 1/2, so at P(1,-11)
y+11 = 1/2 (x-1)
a) P is the point on the curve y= 2x^3 +kx -5 where x= 1 and gradient is -2.
Find
(i) The value of the constant k
(ii) The equation of the normal to the curve at P
1 answer