If the number is x, then
x = 10t+5
so,
10t+5 = 7(mod 11)
10t = 2(mod 11)
so, which multiple of 10 leaves a remainder of 2 when divided by 11? How about 90 = 88+2?
So, t=9
95 = 10*9+5 = 11*8+7
A number on being divided by 10 and 11 successively leaves the remainders 5 and 7. Find the number.
ie, x/10 = remainder 5 and
x/11 = remainder 7.
please help me to find the value of x.
1 answer
1 answer