A number has a remainder of 2 when divided by 5 and also has a remainder of two when divided by 3. Please find the biggest possible value of this two digit number.

Answer 1

To find the biggest possible value of this two digit number, we first need to find a number that satisfies both conditions.

Let's call the number we are looking for "x".

We know that x divided by 5 gives a remainder of 2, so we can write x = 5n + 2, where n is an integer.

We also know that x divided by 3 gives a remainder of 2, so we can write x = 3m + 2, where m is an integer.

Now we have two equations:

5n + 2 = 3m + 2
5n = 3m

Since we are looking for a two digit number, n must be greater than or equal to 2 (since the remainder when divided by 5 will be at least 2).

The biggest possible value of n can be 2, which gives us:

x = 5(2) + 2 = 12

Therefore, the biggest possible value of this two digit number is 12.