A number cube with sides numbered 1 throughout 6 is rolled 12 times the results are show in the list 1 6 4 1 1 1 5 2 4 4 3 3. The number cube landed on 4 fewer or more times than expected

1 answer

To determine how many times the number cube landed on 4 compared to what we would expect, we first need to calculate the expected frequency of rolling a 4 when rolling the cube 12 times.

A fair number cube (with sides numbered from 1 to 6) will have an equal probability of landing on each number. Therefore, the probability of rolling a 4 is:

\[ P(\text{rolling a 4}) = \frac{1}{6} \]

With 12 rolls, the expected number of times we would roll a 4 is:

\[ \text{Expected number of 4s} = 12 \times \frac{1}{6} = 2 \]

Next, we count how many times 4 appears in the given results:
The list of rolls is: 1, 6, 4, 1, 1, 1, 5, 2, 4, 4, 3, 3.

From this list, we can see that the number 4 occurs 3 times.

Now we can compare the actual number of times a 4 was rolled (which is 3) to the expected number (which is 2):

\[ \text{Difference} = \text{Actual} - \text{Expected} = 3 - 2 = 1 \]

Therefore, the number cube landed on 4 1 time more than expected.