X+y=9
10x+y-45=10y+x
solve it an algebra now
a number consists of two digits whose sum is 9. if 45 is subtracted from the number its digits are interchanged. find the number.
6 answers
X+y=9
10x+y-45=10y+x
x+y=9.......(1)
10x-x+y-10y=45
9x-9y=45
9(x-y)=45
x-y=45
-----
x+y=9
x-y=5
2x=14
x=7
your turn finish it
7+y=9
y=9-7
y=2
the number is 72
10x+y-45=10y+x
x+y=9.......(1)
10x-x+y-10y=45
9x-9y=45
9(x-y)=45
x-y=45
-----
x+y=9
x-y=5
2x=14
x=7
your turn finish it
7+y=9
y=9-7
y=2
the number is 72
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