A Nordic jumper goes off a ski jump at an angle of 10.0° below the horizontal, traveling 109.0 m horizontally and 44.0 m vertically before landing. (a) Ignoring friction and aerodynamic effects, calculate the speed needed by the skier on leaving the ramp.

Answer 1

h = 0.5g*t^2 = 44 m.
4.9t^2 = 44
t^2 = 8.98
t = 3 s. = Time in flight.

Range = Vo*cos10 * t = 109 m.
Vo*cos10 * 3 = 109
Vo = 109/3*cos10 = 36.9 m/s[10o]