number of dimes --- x
number of quarters -- x+10
number of nickels = 2(x+10)
now for the "value":
10x + 25(x+10) + 5(2(x+10)) = 530
solve for x, then plug into my definitions.
A newspaper carrier has $5.30 in change. He has ten more quarters than dimes but two times as many nickles as quarters. How many coins of each type does he has?
1 answer