A new shipment of 9 VCRs, which will be offered at a very low price, are delivered, Unknown to the manager, 4 of the VCRs are defective, Determine the probability that at least 1 of the first three VCRs sold is defective.Did I do this right? 1-5C3/9C3 =88.09% or do I do 1-(5/9)^3 = 82.9%. Please help I don't understand why the different methods are yielding a different answer. They should be the same. Help please!
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