The total moment of inertia of the ride can be calculated as follows:
I = 80(35 kg m²) + 80(250 kg)(15 m)²
I = 807,500 kg m²
The kinetic energy of the ride can be calculated using the formula:
K = (1/2)Iω²
where ω is the angular speed in radians per second.
Plugging in the values, we get:
K = (1/2)(807,500 kg m²)(0.21 rad/s)²
K = 15,585.53 J
Therefore, the total kinetic energy of the ride during a test run with empty carts is 15,585.53 J.
A new ride is being designed for Dubailand. The ride will have 80 identical carts placed 15 m away from the center. Each cart has a mass of 250 kg. If the moment of inertia of each connecting rod system is 35 kg m² and the ride spins with an angular speed of 0.21 rad/s, what is the total kinetic energy of the ride during a test run with empty carts?
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