A new crew of painters takes two times as long to paint a small apartment as an experienced crew. Together, both crews can paint the apartment in 6

hours. How many hours does it take the experienced crew to paint the apartment?

It takes blank hours for the experienced crew to paint the apartment.

7 answers

Let \( x \) be the time it takes the experienced crew to paint the apartment (in hours). According to the problem, the new crew takes twice as long, so it takes the new crew \( 2x \) hours to paint the apartment.

The rates of work for each crew can be expressed as follows:

  • The rate of the experienced crew is \( \frac{1}{x} \) apartments per hour.
  • The rate of the new crew is \( \frac{1}{2x} \) apartments per hour.

When both crews work together, their combined rate is:

\[ \frac{1}{x} + \frac{1}{2x} = \frac{2}{2x} + \frac{1}{2x} = \frac{3}{2x} \text{ apartments per hour.} \]

Given that together they can paint the apartment in 6 hours, their combined work rate must equal the rate needed to complete one apartment in 6 hours:

\[ \frac{3}{2x} = \frac{1}{6}. \]

Next, we can solve for \( x \) by cross-multiplying:

\[ 3 \cdot 6 = 2x \cdot 1, \]

which simplifies to:

\[ 18 = 2x. \]

Now, divide both sides by 2:

\[ x = 9. \]

Thus, it takes the experienced crew \( 9 \) hours to paint the apartment.

Therefore, the answer is:

It takes 9 hours for the experienced crew to paint the apartment.

Consider the coconuts

The "coconuts problem" is a classic riddle that involves a scenario with coconuts and involves a series of events where the total amount of coconuts is divided among people. Here’s a common version of the riddle:


Problem: A group of n sailors (or people) found a pile of coconuts on an island. They decided to divide them up at night, but each sailor wanted to make sure he had the most coconuts. So, they made a plan to take turns.

On the first sailor's turn, it is said that he took half of the coconuts, plus one additional coconut, then he left the remaining coconuts for the others. The next sailor did the same thing with the remaining coconuts. This process continues until all sailors have taken their turn. In the end, there is one coconut left.


For the generalized riddle, your task is to determine how many coconuts were in the pile initially.

Solution Approach:

Let's set up the problem mathematically.

Let’s denote the total number of coconuts initially as \(C\).

  1. The first sailor takes \( \frac{C}{2} + 1 \) coconuts, leaving \( C - \left(\frac{C}{2} + 1\right) = \frac{C}{2} - 1 \).
  2. The second sailor then takes half of the remaining coconuts plus one: \( \frac{\frac{C}{2} - 1}{2} + 1 = \frac{C}{4} - \frac{1}{2} + 1 = \frac{C}{4} + \frac{1}{2} \), leaving \( \frac{C}{2} - 1 - \left(\frac{C}{4} + \frac{1}{2}\right) = \frac{C}{4} - \frac{3}{2} \).
  3. This continues for all sailors, until the last sailor leaves one coconut remaining.

Reverse Reasoning:

Instead of moving forward, we can start from the end (1 coconut remaining) and work backward to find the total coconuts.

  1. If \( x \) is the number of coconuts before the last sailor takes his share, then he must have taken \( \frac{x}{2} + 1 \) such that \( x - \left(\frac{x}{2} + 1\right) = 1 \).
  2. Simplifying gives: \[ x - \frac{x}{2} - 1 = 1 \Rightarrow \frac{x}{2} = 2 \Rightarrow x = 4. \]

Repeat this backwards for each sailor until all sailors are accounted for and you’ll determine the original number of coconuts.

Would you like me to solve for a specific number of sailors or a specific version of the coconuts problem?

If I go into zoom class for my teacher can they see my birthday if I turn my cam on? I’m on phone and had to log into with a different account since I’m not on my computer and I had to put a false date in since I’m not 16.. I will be next year but yeah

In a typical Zoom class, your teacher cannot see your personal information, such as your birthday, just by turning on your camera. The camera will only show your video feed, so they will only see you (or whatever is in front of the camera).

However, if you logged into Zoom with an account that requires you to provide personal information (like your birthday) and you entered a false date, your teacher will not be able to view that information unless they have access to your account details, which they typically do not.

It's always a good idea to be cautious about the information you provide online. If you're uncertain about privacy settings or account information, you might want to review the privacy policy or settings of the platform you're using.

What time was it 18 hours ago and 38 minutes. It’s December 13th at 9:12 am

To find out what time it was 18 hours and 38 minutes ago from December 13th at 9:12 AM, we can break this down into two parts: first subtracting 18 hours, then subtracting 38 minutes.

  1. Subtracting 18 hours from 9:12 AM:
    • 9:12 AM minus 18 hours:
    • 9:12 AM - 12 hours = 9:12 PM (of the previous day, December 12th).
    • Then subtracting an additional 6 hours (18 - 12 = 6):
    • 9:12 PM - 6 hours = 3:12 PM (of the previous day, December 12th).

So after subtracting 18 hours, it is now 3:12 PM on December 12th.

  1. Subtracting 38 minutes from 3:12 PM:
    • 3:12 PM - 38 minutes = 2:34 PM.

Therefore, 18 hours and 38 minutes ago from December 13th at 9:12 AM was 2:34 PM on December 12th.