To find the surface area of the rectangular pyramid, we need to find the area of each of the faces and add them together.
1. The base of the pyramid is a rectangle with dimensions 7 inches by 9 inches, so its area is 7 * 9 = 63 square inches.
2. The four triangular faces are isosceles triangles. The area of each triangular face is (1/2) * base * height.
The area of the larger triangular face is (1/2) * 9 * 8 = 36 square inches.
The area of the smaller triangular face is (1/2) * 7 * 8.5 = 29.75 square inches.
Therefore, the total surface area of the rectangular pyramid is:
63 + 36 + 36 + 29.75 + 29.75 = 194.5 square inches.
So, the surface area of the rectangular pyramid is 194.5 in2.
Therefore, the correct option is:
194.5 in2
A net of a rectangular pyramid is shown in the figure.
A net of a triangular prism with base dimensions of 7 inches by 9 inches. The larger triangular face has a height of 8 inches. The smaller triangular face has a height of 8.5 inches.
What is the surface area of the pyramid?
97.25 in2
131.5 in2
194.5 in2
257.5 in2
1 answer