A net horizontal force F =A +Bt^3 acts on a 2kg object, where A = 5N and B = 2N/s3. What is the horizontal velocity of this object 4.0 seconds after it starts from rest?

Question

F=ma=5+2t^3
a=2.5+t^3

V=2.5t+(1/4)(t^3)
therefore, at t=4, V=74m/s

Is this correct?

Answer 1

V=2.5t+t^4