I= Δq/Δt =47•10^-3/19 = ...
N = Δq/e = 47•10^-3/1.6•10^-19 = ...
A net charge of 47 mC passes through the cross-sectional area of a wire in 19.0 s.
(a) What is the current in the wire?
1 A
(b) How many electrons pass the cross-sectional area in 1.0 min?
2 electrons
1 answer
1 answer