A "neon" sign contains 2.4¡Ñ10^2 mL of argon. Assuming that the gas is at standard temperature and pressure, there is 1.00 moles of gas per 22.4 L of volume. How many argon atoms are present in this sign?

Question

(a)6.5¡Ñ10^21
(b)2.8¡Ñ10^22
(c)3.2¡Ñ10^24
(d)9.9¡Ñ10^-23

Answer 1

I can't decipher the hieroglyphics.

Answer 2

what's the ¡Ñ???..unless it don't matter, then just convert the mL to liters such that;

240mL becomes 0.24L.

using the convention 1mole = 22.4L, find the mole for the 0.24L.
i.e. 0.24L/22.4 = 1.07e-2moles.

using avogadros number;
1mole = 6.02e23 atoms

i.e. 1.07e-2moles x 6.02e23 = 0.0645e23 atoms

unless the ¡Ñ matters to the unit, then you have to recheck the conversion and follow the same method above...

hope that helps...