P = Es*Is = 150,000 Watts
120*Is = 150,000
Is = 1250 Amps. = Current flowing through secondary coils.
Ip = 140/25000 * 1250 = 7 Amps = current
through primary coils and transmission lines.
A neighbourhood requires 1.5 x 10^5 w of electricity to power all homes during peak usage times. A step-down transformer is used on the high voltage transmission lines to lower the voltage to 120v for household use. There are 25000 primary coils and 140 secondary coils on the transformer. What current flows through the high voltage transmission lines during this time?
1 answer
1 answer