Eq = F
E = F/q
E = 0.12N / 3 x 10^-4 C
E = 400 N/C
Therefore, the magnitude of the field intensity is 400 N/C.
A negative charge of 3 x 10-4 C experiences a force of 0.12N when in an electric field. What is the magnitude of the field intensity?
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A negative charge of 3 x 10-4 C experiences a force of 0.12N when in an electric field. What is the magnitude of the field intensity? Equation Used Assign value to the variable Show Your Work Answer with Units
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