F = qE
0.12N = (3 x 10-4 C)E
E = 0.12N / (3 x 10-4 C)
E = 4 x 104 N/C
Answer: The magnitude of the field intensity is 4 x 104 N/C.
A negative charge of 3 x 10-4 C experiences a force of 0.12N when in an electric field. What is the magnitude of the field intensity? Show your work and answer with correct units.
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