A NASCAR driver weighing 75 kg enters a corner with a radius of 155 m with a speed of 125 m/s. What is the centripetal force that maintains his circular motion?

Answer 1

The centripetal force can be calculated using the formula:

Fc = (mv^2) / r

Where:
Fc = centripetal force
m = mass of the driver (75 kg)
v = velocity of the driver (125 m/s)
r = radius of the corner (155 m)

Fc = (75 kg)(125 m/s)^2 / 155 m
Fc = (75)(15625) / 155
Fc = 1171875 / 155
Fc = 7567.74 N

Therefore, the centripetal force that maintains the NASCAR driver's circular motion is approximately 7567.74 N.