A(n) 94 kg clock initially at rest on a horizontal

floor requires a(n) 697 N horizontal
force to set it in motion. After the clock is in
motion, a horizontal force of 530 N keeps it
moving with a constant velocity.
The acceleration of gravity is 9.81 m/s2
Find µk between the clock and the floor.

1 answer

forcefriction=uk*mg
uk=530/(98*9.8)