A movie theater offers two options for membership. The first option costs $15 per ticket but an initial fee of $10. The second option costs $10 per ticket but an initial fee of $45. After how many tickets are both options the same price?

__ tickets

1 answer

Let's assume the number of tickets needed for both options to be the same price is x.

For the first option, the cost is $15 per ticket with an initial fee of $10. So the total cost for x tickets can be represented as 15x + 10.

For the second option, the cost is $10 per ticket with an initial fee of $45. So the total cost for x tickets can be represented as 10x + 45.

Since we want the total cost for x tickets to be the same for both options, we can set the equations equal to each other:

15x + 10 = 10x + 45

Subtracting 10x and 10 from both sides:

5x = 35

Dividing both sides by 5:

x = 7

Therefore, both options will be the same price after 7 tickets.