a mover uses a ramp to pull a 1000 newton cart up to the floor of his truck 0.8 meters high if it takes a force or 200 newtons to pull the cart what is the length of the ramp

Answer 1

The answer depends upon the amount of friction. If there is no friction, they should have said so.

In the frictionless case,
(Force) x (ramp length) = (weight) x (height)

To approximate frictionless behavior, the cart should have well lubricated wheels.

Answer 2

200*0.8=160

Answer 3

tu madre

Answer 4

4m

Answer 5

First, calculate the Mechanical Advantage by using MA = effort / load where effort is 200N (using 200N of effort to pull the cart) and load is 1000N (the cart exerts a force of 1000N on the ramp - the ramps load). 200N / 1000N = 5. Then use the ideal mechanical advantage formula for a ramp: IMA = length / height where IMA is the MA that we just calculated - 5, and height is 0.8m. Set up the equation like this: 5 = length / 0.8m = 4m

Answer 6

Graham is partially right. MA= LOAD/EFFORT which gives you 1000N/200N = 5. 200N/1000N= 0.2. So now, 5 = length / 0.8m. Multiply both sides by 0.8m in order to isolate length. 5 x 0.8m = length = 4m