A mouse is running away from a cat at. 75 m/s and, at 1.25 m from his mouse hole, he accelerates at a constant rate of. 25 m/s^2 until he reaches his hole safely. How long a time was required for him to cover te last 1.25m?

Answer 1

use the formula:
S = ut +(1/2)*a*t^2

S - distance covered =1.25m
u - initial velocity = 75m/s^2
a - acceleration = 25m/s^2
t - time taken to cover the distance

Answer 2

1.4