Asked by Lily
A mountain biker rides a given distance due north, then drives twice that far to the west. At the end of the trip the direct distance from the starting point is 112meters. What is the length of each leg of the trip and in which direction is the end point?
Answers
Answered by
Henry
d^2 = (2n)^2 + n^2 = 112^2
4n^2 + n^2 = 12,544
5n^2 = 12544
n^2 = 2508.8
n = 50 m. = North leg.
2n = 100 m. = West leg.
tan A = 2n/n = 2.0
A = 63.43o West of North = Direction.
4n^2 + n^2 = 12,544
5n^2 = 12544
n^2 = 2508.8
n = 50 m. = North leg.
2n = 100 m. = West leg.
tan A = 2n/n = 2.0
A = 63.43o West of North = Direction.
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