In the zero-friction case, ZERO work and no power is required on a flat (level) road.
If the coefficient of kinetic friction is 0.012, a force of
F = 0.012 M g = 353 N is required to push the car. (That is about 80 lb)
Use that for the work and power required.
Work = F * X
Power = F*X/(600 seconds)
a motorist runs out of gas and must push his 3000kg car across a flat road 200m to the gas station. ignoring friction how much work must be done in order to get the car to the gas pump? if the motorist accomplishes this in 10 minutes, how much power has he applied? what if the coefficient of kinetic friction is u= 0.012? how much work is done? how much power is applied?
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