A motorcyclist starting from rest is uniformly accelerated such that its velocity in 10s is 72kmhr. what is its acceleration

Answer 1

To solve this problem, we can use the formula for uniformly accelerated motion:

v = u + at

Where:
v = final velocity (72 km/hr)
u = initial velocity (0 km/hr, as the motorcyclist starts from rest)
t = time (10 s)
a = acceleration (unknown)

First, we need to convert the velocity from km/hr to m/s because the standard unit of acceleration is m/s²:

1 km/hr = 1000 m/3600 s = 5/18 m/s

Therefore, the final velocity is 72 km/hr × 5/18 m/s = 20 m/s.

Now, we can rearrange the formula to solve for acceleration:

a = (v - u) / t

Plugging in the values we have:

a = (20 m/s - 0 m/s) / 10 s
a = 20 m/s / 10 s
a = 2 m/s²

Therefore, the acceleration of the motorcyclist is 2 m/s².