To solve this problem, we can use the formula for uniformly accelerated motion:
v = u + at
Where:
v = final velocity (72 km/hr)
u = initial velocity (0 km/hr, as the motorcyclist starts from rest)
t = time (10 s)
a = acceleration (unknown)
First, we need to convert the velocity from km/hr to m/s because the standard unit of acceleration is m/s²:
1 km/hr = 1000 m/3600 s = 5/18 m/s
Therefore, the final velocity is 72 km/hr × 5/18 m/s = 20 m/s.
Now, we can rearrange the formula to solve for acceleration:
a = (v - u) / t
Plugging in the values we have:
a = (20 m/s - 0 m/s) / 10 s
a = 20 m/s / 10 s
a = 2 m/s²
Therefore, the acceleration of the motorcyclist is 2 m/s².
A motorcyclist starting from rest is uniformly accelerated such that its velocity in 10s is 72kmhr. what is its acceleration
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