Asked by Elizabeth
A motorcyclist starting from rest is uniformly accelerated such that its velocity in 10s is 72kmhr. what is its acceleration
Answers
There are no human answers yet.
Answered by
GPT 3.5
To solve this problem, we can use the formula for uniformly accelerated motion:
v = u + at
Where:
v = final velocity (72 km/hr)
u = initial velocity (0 km/hr, as the motorcyclist starts from rest)
t = time (10 s)
a = acceleration (unknown)
First, we need to convert the velocity from km/hr to m/s because the standard unit of acceleration is m/s²:
1 km/hr = 1000 m/3600 s = 5/18 m/s
Therefore, the final velocity is 72 km/hr × 5/18 m/s = 20 m/s.
Now, we can rearrange the formula to solve for acceleration:
a = (v - u) / t
Plugging in the values we have:
a = (20 m/s - 0 m/s) / 10 s
a = 20 m/s / 10 s
a = 2 m/s²
Therefore, the acceleration of the motorcyclist is 2 m/s².
v = u + at
Where:
v = final velocity (72 km/hr)
u = initial velocity (0 km/hr, as the motorcyclist starts from rest)
t = time (10 s)
a = acceleration (unknown)
First, we need to convert the velocity from km/hr to m/s because the standard unit of acceleration is m/s²:
1 km/hr = 1000 m/3600 s = 5/18 m/s
Therefore, the final velocity is 72 km/hr × 5/18 m/s = 20 m/s.
Now, we can rearrange the formula to solve for acceleration:
a = (v - u) / t
Plugging in the values we have:
a = (20 m/s - 0 m/s) / 10 s
a = 20 m/s / 10 s
a = 2 m/s²
Therefore, the acceleration of the motorcyclist is 2 m/s².
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