A motorcyclist is trying to leap across the canyon by driving horizontally off the cliff at a speed of 38.0 m/s, height of the first cliff=50m, second cliff=30m.Ignoring the air resistance, find the speed with which the cycle strikes the ground on the other side.

Answer 1

starting K.E + gravitational P.E. = final K.E.

(1/2 * m * 38.0^2) + [m * 9.8 * (50 - 30)] = 1/2 * m * v^2

dividing by 1/2 m ... 38.0^2 + (2 * 9.8 * 20) = v^2