A motorcycle traveling 92.0 km/hr approaches a car traveling in the same direction at 82.0 km/hr. When the motorcycle is 51.0 m behind the car, the rider accelerates and passes the car 15.0 s later. What is the acceleration of the motorcycle (in meters/second^2)?

Answer 1

(v * t) + (1/2 * a * t^2) = V * t

convert the motorcycle (v) and car (V) velocities to m/s