A motorcycle racer falls off their motorbike while traveling at 102 km/hr and skids in a straight line down the track. If the friction with the track decelerates the rider at a uniform rate of 4.6 m/s/s, how far (what displacement) would the rider travel before coming to a stop?

Question

oobleck · Accepted Answer

102 km/hr = 28.33 m/s Now, as usual, v = 28.33 - 4.6t find t when v=0, and then s = 28.33t - 2.3t^2

Evan · Answer

I'm still lost on what the answer is? how did you get 28.33 m/s?

bobpursley · Answer

102 km/hr = 28.33 m/s from 102km/hr*1000m/km*1hr/3600sec= 28.33 m/s If you are serious with this question, you need some tutoring on unit conversion very quickly.

Yashvi · Answer

Hi, im just curious and would appreciate it if someone replied. Would the answer be 87.24 m?