Dc = 19t = Distance of the car after t1.
Dm = Vo*t + 0.5a*t^2 = Distance of motorcycle after t1.
Dm = Dc + 52
Vo*t + 0.5a*t^2 = 19t + 52
19*t + 2.5*t^2 = 19t + 52
19t - 19t + 2.5*t^2 = 52
t^2 = 20.8
t = 4.56 s.
So the motorcycle caught-up 4.56 s after
it started to accelerate.
A motorcycle is following a car that is traveling at constant speed on a straight highway. Initially, the car and the motorcycle are both traveling at the same speed of 19.0m/s , and the distance between them is 52.0m . After t1 = 5.00s , the motorcycle starts to accelerate at a rate of 5.00m/s2. How long does it take from the moment when the motorcycle starts to accelerate until it catches up with the car? In other words, find t2−t1
4 answers
A rock is thrown directly upward from the edge of the roof of a building that is 58.7 meters tall. The rock misses the building on its way down, and is observed to strike the ground 4.00 seconds after being thrown. Neglect any effects of air resistance. With what speed was the rock thrown?
4.56 s
A relative density bottle weight 20g when empty, 80g when field with water and 100g when with a liquid. Fine the relative density of liquid.