A motorcycle has a velocity of 15 m/s due south as it passes a car with a velocity of 24m/s due north. What is the magnitude and direction of the velocity of the motorcycle an seen by the driver of the car.
2 answers
(24+15) m/s south
call north positive
Vmc = -15
Vcar = +24
Vrelative= Vmc - Vcar = -15 - 24 = - 39
39 south
Vmc = -15
Vcar = +24
Vrelative= Vmc - Vcar = -15 - 24 = - 39
39 south