(a) M V^2/R = 364*(24.4)^2/135
= 1605 newtons
(b) weight - (normal force) = centripetal force
normal force = Mg - 1605 = 3571 - 1605
= 1966 newtons
That is the vertical force exerted by the road on the motorcycle at the top of the hill.
A motorcycle has a constant speed of 24.4 m/s as it passes over the top of a hill whose radius of curvature is 135 m. The mass of the motorcycle and driver is 364 kg. Find the magnitude of (a) the centripetal force and (b) the normal force that acts on the cycle.
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