A motor lifts a 70.0 kg box off the ground, starting from rest. In 8.00 seconds it lifts the box to a height of 20.0 m. At that time, the box is moving upward with a velocity of 5.00 m/s. What is the average power of the motor during this time interval?

Answer 1

P =W/t = ΔE/t = (m•g•h +m•v²/2)/t

Answer 2

1820w

Answer 3

P =W/t = ΔE/t = (m•g•h +m•v²/2)/t